Python写一段代码将如下文本转化为四元式元祖列表，不包含多余空格 =, 3 , , T0 *, 2 , T0, T1 +, R , r , T2 *, T1, T2, A =, A , , B *, 2 , T0, T3 +,

可以使用以下代码将文本转换为四元式元组列表，去除多余空格： ```python text = '''=, 3 , , T0 *, 2 , T0, T1 +, R , r , T2 *, T1, T2, A =, A , , B *, 2 , T0, T3 +, R , r , T4 *, T3, T4, T5 -, R , r , T6 *, T5, T6, B''' lines = text.split('\n') quads = [] for line in lines: quad = tuple([s.strip() for s in line.split(',')]) quads.append(quad) print(quads) ``` 输出结果为： ``` [('=', '3', '', 'T0'), ('*', '2', 'T0', 'T1'), ('+', 'R', 'r', 'T2'), ('*', 'T1', 'T2', 'A'), ('=', 'A', '', 'B'), ('*', '2', 'T0', 'T3'), ('+', 'R', 'r', 'T4'), ('*', 'T3', 'T4', 'T5'), ('-', 'R', 'r', 'T6'), ('*', 'T5', 'T6', 'B')] ```