好的,下面是一个能自动对输入的四元式进行基本块划分并利用 DAG 进行优化的 Python 代码:
```python
from typing import List
from collections import deque
class Quadruple:
def __init__(self, op: str, arg1: str, arg2: str, res: str):
self.op = op
self.arg1 = arg1
self.arg2 = arg2
self.res = res
def __str__(self):
return f'({self.op}, {self.arg1}, {self.arg2}, {self.res})'
def split_basic_blocks(quadruples: List[Quadruple]) -> List[List[Quadruple]]:
basic_blocks = []
current_block = []
for q in quadruples:
current_block.append(q)
if q.op == 'goto' or q.op == 'if':
basic_blocks.append(current_block)
current_block = []
if current_block:
basic_blocks.append(current_block)
return basic_blocks
class DAGNode:
def __init__(self, op: str, arg1: str, arg2: str, res: str):
self.op = op
self.arg1 = arg1
self.arg2 = arg2
self.res = res
self.parents = []
self.children = []
def __str__(self):
return f'({self.op}, {self.arg1}, {self.arg2}, {self.res})'
class DAG:
def __init__(self, quadruples: List[Quadruple]):
self.nodes = {}
self.roots = []
for q in quadruples:
if q.op == '=':
node = DAGNode(q.op, q.arg1, None, q.res)
else:
node = DAGNode(q.op, q.arg1, q.arg2, q.res)
if node.res in self.nodes:
existing_node = self.nodes[node.res]
existing_node.parents.append(node)
node.children.append(existing_node)
self.nodes[node.res] = node
else:
self.nodes[node.res] = node
self.roots.append(node)
def generate_code(self) -> List[Quadruple]:
optimized_quadruples = []
visited = set()
for root in self.roots: