Check if current_node exists. Call the in_order() function recursively on the appropriate half of the tree. Print the va

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小小草
小小草 LV1 2023年9月23日 23:40 发表
Here's the completed code: ``` class BinarySearchTree: def __init__(self): self.root = None def in_order(self, current_node): # Check if current_node exists if current_node: # Call recursively with the appropriate half of the tree self.in_order(current_node.left_child) # Print the value of the current_node print(current_node.data) # Call recursively with the appropriate half of the tree self.in_order(current_node.right_child) bst = BinarySearchTree() bst.in_order(bst.root) ``` The code defines a BinarySearchTree class with an in_order method that performs an in-order traversal of the tree. It takes a current_node parameter that specifies the root of the subtree to traverse. It starts by checking whether the current node exists. If it does, it calls the in_order method recursively on the left child of the current node, which traverses the left subtree. Then, it prints the data of the current node, which is the root of the subtree. Finally, it calls the in_order method recursively on the right child of the current node, which traverses the right subtree. This process continues until all nodes in the tree have been visited. Finally, it creates a BinarySearchTree object and calls the in_order method with the root of the tree as the parameter to perform an in-order traversal of the entire tree.
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