上下水管的位置随机出现

好的，以下是实现上下水管位置随机出现的代码： ```python import pgzrun from random import randint import keyboard WIDTH = 400 HEIGHT = 708 bird = Actor('bird1', (75, 350)) pipes = [] for i in range(3): pipe_top = Actor('top', (500 + i * 200, 0)) pipe_bottom = Actor('bottom', (500 + i * 200, 500)) pipes.append((pipe_top, pipe_bottom)) game_over = False score = 0 def update(): global game_over, score if not game_over: bird.y += 2 for pipe_top, pipe_bottom in pipes: pipe_top.x -= 2 pipe_bottom.x -= 2 if pipe_top.right < 0: pipe_top.left = WIDTH pipe_bottom.left = WIDTH pipe_top.y = randint(-250, -50) pipe_bottom.y = pipe_top.y + 800 score += 1 if bird.colliderect(pipe_top) or bird.colliderect(pipe_bottom): game_over = True if bird.bottom > HEIGHT: game_over = True if keyboard.space: bird.y -= 50 def draw(): screen.blit('background', (0, 0)) for pipe_top, pipe_bottom in pipes: pipe_top.draw() pipe_bottom.draw() bird.draw() screen.draw.text(str(score), (10, 10), color='white', fontsize=30) if game_over: screen.draw.text('Game Over!', center=(WIDTH/2, HEIGHT/2), color='white', fontsize=60) pgzrun.go() ``` 在这个修改后的代码中，我们在每个水管出现时随机生成上下水管的位置。具体来说，我们使用randint函数生成一个随机数作为上水管的y坐标，然后将下水管的y坐标设置为上水管的y坐标加上800（即两个水管之间的距离）。这样就可以实现上下水管位置随机出现了。